![]() Apply the same technique you completed in part (d), but instead of calculating the time t when the object’s position is 0, calculate the time t when its position is 6. (e) The problem asks you to calculate the velocity of the object when it is exactly six feet off of the ground, when s( t) = 6. Set the position equation equal to zero and solve for t. (d) The object hits the ground when its position is s( t) = 0. ![]() (c) Substitute t = 1, 2, and 3 into v( t). Apply the slope formula from basic algebra to calculate the slope of the line passing through those points. Plug t = 2 and t = 3 into the position equation to calculate the height of the object at the boundaries of the indicated interval to generate two ordered pair: (2, 1478) and (3, 1398). (b) Average velocity is the slope of the secant line, rather than the slope of the tangent line. The vecocity equation v( t) is the derivative of the position equation: v( t) = –32 t. Thus, the position equation is s( t) = –16 t2 + 1,542. Note that this position equation represents the height in feet of the object t seconds after it is released. (a) The position function for a projectile is s( t) = –16 t2 + v0 t + h0, where v0 represents the initial velocity of the object (in this case 0) and h0 represents the initial height of the object (in this case 1,542 feet). (e) If the object were to hit a six-foot-tall man squarely on the top of the head as he (unluckily) passed beneath, how fast would the object be moving at the moment of impact? Report your answer accurate to the thousandths place. ![]() (d) How many seconds does it take the object to hit the ground? Report your answer accurate to the thousandths place. (c) Compute the velocity of the object 1, 2, and 3 seconds after it is released. ![]() (b) Calculate the average velocity of the object over the interval t = 2 and t = 3 seconds. (a) Construct the position and velocity equations for the object in terms of t, where t represents the number of seconds that have elapsed since the object was released. An object is dropped from the second-highest floor of the Sears Tower, 1542 feet off of the ground. ![]()
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